1,f(5.5)=-f(3.5)=f(1.5)=-f(-0.5)=f(0.5)=0.52,2a^2+a+2>0,3a^2-2a+4>0,因为f(x)是偶函数,所以在(0,正无穷)递减2a^2+a+2>3a^2-2a+4,a^2-3a+2<0,(a-1)(a-2)<010f'(x)=1/(x^2)(2x^3-a)>0a<2x^3<=16a<=164,f(x)=1/(x^2-1)g(x)=x/(x^2-1)5,0<=x^2+1<=1所以-1<=x^2<=0x=06,最小-3最大3孩子别依赖百度自己好好想想考试时不能百度的这些题目输输也烦的吧。。。7,-3